format.c 4.7 KB

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  1. // SPDX-License-Identifier: Apache-2.0
  2. #include <stdint.h>
  3. void hex_encode(char *output, uint8_t *input, uint32_t length)
  4. {
  5. for (int i = 0; i < length; i++)
  6. {
  7. uint8_t h = (input[i] >> 4);
  8. *output++ = h > 9 ? h + 'a' - 10 : '0' + h;
  9. uint8_t l = (input[i] & 0x0f);
  10. *output++ = l > 9 ? l + 'a' - 10 : '0' + l;
  11. }
  12. }
  13. void hex_encode_rev(char *output, uint8_t *input, uint32_t length)
  14. {
  15. for (int i = length - 1; i >= 0; i--)
  16. {
  17. uint8_t h = (input[i] >> 4);
  18. *output++ = h > 9 ? h + 'a' - 10 : '0' + h;
  19. uint8_t l = (input[i] & 0x0f);
  20. *output++ = l > 9 ? l + 'a' - 10 : '0' + l;
  21. }
  22. }
  23. char *uint2hex(char *output, uint8_t *input, uint32_t length)
  24. {
  25. // first count how many characters
  26. while (length > 1 && input[length - 1] == 0)
  27. length--;
  28. *output++ = '0';
  29. *output++ = 'x';
  30. uint8_t h = (input[length - 1] >> 4);
  31. if (h > 0)
  32. *output++ = h > 9 ? h + 'a' - 10 : '0' + h;
  33. uint8_t l = (input[length - 1] & 0x0f);
  34. *output++ = l > 9 ? l + 'a' - 10 : '0' + l;
  35. while (--length)
  36. {
  37. uint8_t h = (input[length - 1] >> 4);
  38. *output++ = h > 9 ? h + 'a' - 10 : '0' + h;
  39. uint8_t l = (input[length - 1] & 0x0f);
  40. *output++ = l > 9 ? l + 'a' - 10 : '0' + l;
  41. }
  42. return output;
  43. }
  44. char *uint2bin(char *output, uint8_t *input, uint32_t length)
  45. {
  46. // first count how many bytes
  47. while (length > 1 && input[length - 1] == 0)
  48. length--;
  49. *output++ = '0';
  50. *output++ = 'b';
  51. uint8_t v = input[length - 1];
  52. int i = 8;
  53. while (i > 0 && !(v & 0x80))
  54. {
  55. v <<= 1;
  56. i--;
  57. }
  58. while (i--)
  59. {
  60. *output++ = v & 0x80 ? '1' : '0';
  61. v <<= 1;
  62. }
  63. while (--length)
  64. {
  65. uint8_t v = input[length - 1];
  66. for (i = 0; i < 8; i++)
  67. {
  68. *output++ = v & 0x80 ? '1' : '0';
  69. v <<= 1;
  70. }
  71. }
  72. return output;
  73. }
  74. char *uint2dec(char *output, uint64_t val)
  75. {
  76. char buf[20];
  77. int len = 0;
  78. // first generate the digits in left-to-right
  79. do
  80. {
  81. buf[len++] = val % 10;
  82. val /= 10;
  83. } while (val);
  84. // now copy them in to right-to-left
  85. while (len--)
  86. {
  87. *output++ = buf[len] + '0';
  88. }
  89. return output;
  90. }
  91. extern int udivmod128(const __uint128_t *dividend, const __uint128_t *divisor, __uint128_t *remainder, __uint128_t *quotient);
  92. char *uint128dec(char *output, __uint128_t val128)
  93. {
  94. // we want 1e19, how to declare such a constant in clang?
  95. const __uint128_t billion = 10000000000;
  96. const __uint128_t divisor = billion * 1000000000;
  97. __uint128_t q, r;
  98. char buf[40];
  99. int len = 0;
  100. // first do the first 19 digits
  101. // divisor is never zero so we can ignore return value
  102. udivmod128(&val128, &divisor, &r, &q);
  103. uint64_t val = r;
  104. do
  105. {
  106. buf[len++] = val % 10;
  107. val /= 10;
  108. } while (val);
  109. /// next 19 digits
  110. udivmod128(&q, &divisor, &r, &q);
  111. val = r;
  112. if (val)
  113. {
  114. // add 0s
  115. while (len < 19)
  116. {
  117. buf[len++] = 0;
  118. }
  119. do
  120. {
  121. buf[len++] = val % 10;
  122. val /= 10;
  123. } while (val);
  124. }
  125. val = q;
  126. if (val)
  127. {
  128. // add 0s
  129. while (len < 38)
  130. {
  131. buf[len++] = 0;
  132. }
  133. do
  134. {
  135. buf[len++] = val % 10;
  136. val /= 10;
  137. } while (val);
  138. }
  139. // now copy them in to right-to-left
  140. while (len--)
  141. {
  142. *output++ = buf[len] + '0';
  143. }
  144. return output;
  145. }
  146. typedef unsigned _BitInt(256) uint256_t;
  147. extern int udivmod256(const uint256_t *dividend, const uint256_t *divisor, uint256_t *remainder, uint256_t *quotient);
  148. char *
  149. uint256dec(char *output, uint256_t *val256)
  150. {
  151. // we want 1e19, how to declare such a constant in clang?
  152. const uint256_t n1e10 = 10000000000;
  153. const uint256_t n1e9 = 1000000000;
  154. uint256_t divisor = n1e10 * n1e9;
  155. uint256_t q = *val256, r;
  156. char buf[80];
  157. int len = 0;
  158. // do the first digits
  159. for (int digits = 0; digits < 76; digits += 19)
  160. {
  161. // divisor is never zero so we can ignore return value
  162. udivmod256(&q, &divisor, &r, &q);
  163. uint64_t val = r;
  164. // add 0s
  165. while (len < digits)
  166. {
  167. buf[len++] = 0;
  168. }
  169. do
  170. {
  171. buf[len++] = val % 10;
  172. val /= 10;
  173. } while (val);
  174. if (q == (uint256_t)0)
  175. {
  176. break;
  177. }
  178. }
  179. uint64_t val = q;
  180. if (val)
  181. {
  182. do
  183. {
  184. buf[len++] = val % 10;
  185. val /= 10;
  186. } while (val);
  187. }
  188. // now copy them in to right-to-left
  189. while (len--)
  190. {
  191. *output++ = buf[len] + '0';
  192. }
  193. return output;
  194. }